Math, asked by vineethvishwa9773, 11 months ago

Find the value of sec 15/cosec 75+sin72/cos18-tan33/cot 57

Answers

Answered by sandy1816
14

Step-by-step explanation:

sec15/cosec75+sin72/cos18-tan33/cot57

=sec(90-75)/cosec75+sin(90-18)/cos18 -tan(90-57)/cot57

=cosec75/cosec75+cos18/cos18 -cot57/cot57

=1+1-1

=1

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