find the value of sec60°by appropriate method
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hope it is correct........
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chaishwarya09:
thanks
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Hey User,
♦ Trigonometric Identities ♦
→ Firstly, sec θ = cosec ( 90° - θ )
=> sec 60° = cosec( 90° - 60° ) = cosec 30° = ( 1 / sin 30° ) = 2
→ Or, sec θ = ( 1 / cos θ )
=> sec 60° = ( 1 / cos 60° ) = ( 1 / 1 / 2 ) = 2
→ Or, if you find these methods inappropriate.. or relative, check the attachment and you'll get how sec 60° is found Geometrically...
_________________________________________________________
→ In given equilateral ΔABC, all the angles are 60°
We bisect angle A and as we know, angle bisector in an equilateral triangle perpendicularly bisects the opposite side
=> ∠ADC = 90°
Also, since this is equilateral triangle, ∠ACB = 60°
=> sec 60° = sec ∠ACB = [ AC / CD ]
But, CD = 1/2 BC = 1/2 AC
=> sec 60° = [ AC / ( 1/2 AC ) ] = 2
_________________________________________________________
Here you go √√√
♦ Trigonometric Identities ♦
→ Firstly, sec θ = cosec ( 90° - θ )
=> sec 60° = cosec( 90° - 60° ) = cosec 30° = ( 1 / sin 30° ) = 2
→ Or, sec θ = ( 1 / cos θ )
=> sec 60° = ( 1 / cos 60° ) = ( 1 / 1 / 2 ) = 2
→ Or, if you find these methods inappropriate.. or relative, check the attachment and you'll get how sec 60° is found Geometrically...
_________________________________________________________
→ In given equilateral ΔABC, all the angles are 60°
We bisect angle A and as we know, angle bisector in an equilateral triangle perpendicularly bisects the opposite side
=> ∠ADC = 90°
Also, since this is equilateral triangle, ∠ACB = 60°
=> sec 60° = sec ∠ACB = [ AC / CD ]
But, CD = 1/2 BC = 1/2 AC
=> sec 60° = [ AC / ( 1/2 AC ) ] = 2
_________________________________________________________
Here you go √√√
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