Find the value of Sin 265
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I tried using sin 3x = 3 sin x - 4 sin3x but ended with nasty algebra. sin (3 . 65o) = 3 sin 65 - 4 sin3 65o sin (195o) = 3 sin 65 - 4 sin3 65o sin (180o+15o) = 3 sin 65 - 4 sin3 65o - sin (15o) = 3 sin 65 - 4 sin3 65o ; let sin 65o = x (√2 - √6) / 4 = 3x - 4x3 Can't solve for x Thanks
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