find the value of sin 60 geometrically.
incorrect solution will be reported
Answers
Answered by
2
hey.. Mate, here's ur answer
( For diagram use attachment )
Let,
triangle ABC be an equilateral triangle then,
AB = BC = AC = 2a
AD is perpendicular to BC
also,
AD is median ,
CD = a = BD
angle A = angle B = ang C = 60 degree
In triangle ADC,
AC = 2a
DC = a
AD = √ (2) a - (a) ² = √ 3a ²
therefore,
sin 60 = AD / AC = √3 / 2a
➡ sin60 = √3 / 2
hope it might be helpful
( For diagram use attachment )
Let,
triangle ABC be an equilateral triangle then,
AB = BC = AC = 2a
AD is perpendicular to BC
also,
AD is median ,
CD = a = BD
angle A = angle B = ang C = 60 degree
In triangle ADC,
AC = 2a
DC = a
AD = √ (2) a - (a) ² = √ 3a ²
therefore,
sin 60 = AD / AC = √3 / 2a
➡ sin60 = √3 / 2
hope it might be helpful
Attachments:
Answered by
1
Nice question mate!!!✌✌✌
Refer attachment for understanding the process.
If u find it as most helpful pls mark it as brainliest.
☺ Hope this Helps ☺
Refer attachment for understanding the process.
If u find it as most helpful pls mark it as brainliest.
☺ Hope this Helps ☺
Attachments:
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