Find the value of sin(A+B) +cos(A+B) if triangle ABC is right angled at C
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As angle C=90
So A+B=90
(A+B+C=180...Angle sum property)
Sin (A+B)= Sin90 and Cos(A+B) = Cos 90
Sin90+cos90= 1+0=1
So A+B=90
(A+B+C=180...Angle sum property)
Sin (A+B)= Sin90 and Cos(A+B) = Cos 90
Sin90+cos90= 1+0=1
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