Question

Find the value of (tan1°tan2°tan3°........tan89°)






Plz answer fast and get 20 points!!!

Answer 1

tan1.tan2.........tan89

but tan 89 can be written as cot 1[tan(90-1)=cot 1] by tan(90-theta)=cot(theta)

likewise......,

tan 88 =cot 2

tan 87= cot 3

................up to tan 46=cot 44

then middle one is tan 45 =1

so it is

tan1.tan2...........tan44.tan 45.cot44..............cot1

tan and cot cancel out by[tan (theta)*cot(theta)=1

so ....remaining is 1

answer =1