Question

Find the Value of.
$\frac{1 + {tan }^{2} theta}{1 + {cot}^{2} theta}$
​

Answer 1

Answer:

$\frac{1 + { \tan}^{2}(theta) }{1 + { \cot }^{2} (theta)} \\ \frac{ { \sec}^{2}(theta) }{ { \csc}^{2}(theta)} \\ \frac{ { \sin}^{2}(theta)}{ { \cos }^{2}(theta) } = { \tan }^{2}(theta)$

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Answer 2

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