Question

find the value of
$\sqrt{162 + \sqrt{38 + \sqrt{121} } }$
​

Answer 1

Answer:

Hey mate...

here is your answer :-

Step-by-step explanation:

As we know ,

11 is the square of 121 therefore

$\sqrt{121} = 11$

put the value 11 instead of

$\sqrt{121}$

then add 38 to 11

$\sqrt{38 + 11} = 49$

7 is the square of 49 therefore, put 7 instead of 49

then,

Add 7 and 162

$\sqrt{162 + 7} = 169$

13 is the square of 169 so, put 13 instead of 169

Hence , the answer is 13...

Hope it helps you...!!!

Mark as brainliest :)

Answer 2

Answer is 13

Hooe it helps:)