Question

find the value of the expression (64x^2+81y^2+144xy),when x = 11 and y = 1/5​

Answer 1

Answer:

Here's your answer

Step-by-step explanation:

64x^2+81y^2+144xy

64(11)^2+81(1/5)^2+144(11)(1/5)

64×121+81×1/25+1584×1/5

7744+81/25+1584/5

(193600+81+7920)/25

201601/25