Question

find the value of the following: b2-9(b-1)2 , if b = 11/10​

Answer 1

Step-by-step explanation:

${b}^{2} - 9(b - 1)2 \\ put \: \: b = \frac{11}{10} \\ (\frac{11}{10} ) {}^{2} - 9( \frac{11}{10} - 1) {}^{2} \\ \frac{121}{100} - 9( \frac{11 - 10}{10} ) {}^{2} \\ \frac{121}{100} - 9( \frac{1}{10} ) {}^{2} \\ \frac{121}{100} - 9( \frac{1}{100} ) \\ \frac{121}{100} - \frac{9}{100} \\ \frac{121 - 9}{100} \\ \frac{112}{100}$

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Answer 2

Answer:

2/5 or 0.4

Step-by-step explanation:

b2 -9 (b-1)2

if b= 11/10 ,then,

2* 11/10 -9 (11/10 -1) 2

22/10 -9 ($\frac{11 - 10}{10}$) 2

22/10 -9 * 2/10

22/10 - 18/10 = 11/5 - 9/5

now the dinominators are same ,so subtract directly

= 2/5  

                                         

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