Question

find the value of the following if x=1and y=0 2x^+y^+1​

Answer 1

Hey mate ☺️

Given :

x = 1

y = 0

To Find :

Value of the expression ⤵️⤵️

$2x^{2} + y + 1$

Solution :

$2 {x}^{2} + y + 1 \\ 2 \times {1}^{2} + 0 + 1 \\ = 2 \times 1 + 1 \\ = 2 + 1 \\ = 3$

The value of the expression is 3.

I Hope it helps you ☺️ ✌️ ✌️

Answer 2

Answer:

y=1/2 And x=-1/2

Step-by-step explanation:

Step 1 :

If y=0                                    

2x+y+1=0

2x+0+1=0

2x+1=0

2x=-1

x=-1/2

If x=1

2x+y+1=0

2.1+y+1=0

2+y+1=0

y=-1/-2

y=1/2