Question

find the value of the hcf of 468 and 222and express it in the form of 468m+222n,where m and n are the in tergers

Answer 1

HCF of 468 and 222

468=(222x2) + 24
222 = (24 x 9) + 6
24 = (6 x 4) + 0

Therefore, HCF = 6

6=222-(24x9)
= 222 - {(468 – 222 x 2) x 9 [where 468 = 222 x 2 + 24]
  = 222 - {468 x 9 – 222 x 2 x 9}
= 222 - (468 x 9) + (222 x 18)
= 222 + (222 x 18) - (468 x 9)
= 222[1 + 18] – 468 x 9
   = 222 x 19 – 468 x 9
   = 468 x -9 + 222 x 19

Hence, HCF of 468 and 222 in the form of 468x + 222y is 468 x -9 + 222 x 19.


I hope its help you
mark brainliest

Answer 2

Answer:

hi!! here's your answer

the HCF of 2 numbers can be found by the Euclid's division algorithm

that is a=bq+r

HCF of 468 and 222 isss

468=222(2)+24

222=24(9)+6

24=6(4)+0

thus if is 6

remaining in attachment