Question

Which of the following is ionic
(Electronegativity on Pauling scale
for H = 2.1; F = 4.0; Be = 1.5 and Cs
= 0.7)
(A) HE
(B) CSF
(C) BeF2
(D) all of these​

Answer 1

ANSWER

The electronegativity  of Cs = 0.7 and F = 0.4

Percentage of ionic character =16(χ  

A

​  

−χ  

B

​  

)+3.5(χ  

A

​  

−χ  

B

​  

)  

2

 

Here χ  

A

​  

andχ  

B

​  

 are electronegativity's of two atoms A and B

Percentage of ionic character

=16(0.7−0.4)+3.5(0.7−04)  

2

 =16(0.3)+3.5(0.09)

=4.8+0.315

=5.115

Answer 2

Explanation:

I think that

actually my choice for your question is BeF2

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