Question

Find the value of the quantum number for a hydrogen atom that has an orbital radius of

847pm​

Answer 1

Answer:

Explanation:

The radii of the stationary states of hydrogen atom are

given by the equation

2

0

2

0

0 2

, 1,2,3...

4

Bohr radius 52.92 pm.

n

r n a n

a

me



= =

= =

h

Therefore, the shell with orbital radius of 847 pm will

correspond to principal quantum number

n

given by the

equation

2

2

52.92 847,

or

847 16.00,

52.92

and

4 .

n

n

n