Question

Find the value of the x. Pls do it in details. No unnecessary answer pls

Answer 1

Answer:

2

Step-by-step explanation:

$log_{2 \sqrt{5} }(400) = x \\ log_{20}(400) = x \\ {20}^{2} = {20}^{x} \\ x = 2 \\ formula\: used \\ log_{a}(x) = y \\ so \\ x = {a}^{y}$

Answer 2

We have,

$=> log_{2\sqrt{5}} (400) = x$

$=> 400 = (2\sqrt{5})^x$

$=> 20^2 = (2\sqrt{5})^x$

$=> 20^2 = (\sqrt{20})^x$

$=> 20^2 = (20)^{\frac{x}{2} }$

$=> 2 = \frac{x}{2}$

$=> x = 4$

Therefore, the value of x = 4.

#BeBrainly