Question

find the value of this
6x²+x-40=0​

Answer 1

Answer:

its not a right question.

Answer 2

Hello mate.....

Given.....

$6x {}^{2} + x - 40 = 0 \\ \\ 6x {}^{2} + 16x - 15x - 40 = 0 \\ \\ 6x {}^{2} - 15x + 16x - 40 = 0 \\ \\ 3x(2x - 5) + 8(2x - 5) = 0 \\ \\ (2x - 5)(3x + 8) = 0 \\ \\ 2x - 5 = 0 \: or \: 3x + 8 = 0 \\ \\ 2x = 5 \: or \: 3x = - 8 \\ \\ x = \frac{5}{2} or \frac{ - 8}{3}$

Hope it helps u