find the value of x
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2x
2
+5x+(−12)
Δ
x
1
x
2
=0
↓
=5
2
−(4×2×(−12))
=25−(−96)
=121
↓
=
2×2
−5+√
121
=
4
−5+11
=
4
6
=1.5
↓
=
2×2
−5−√
121
=
4
−5−11
=
4
−16
=−4
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