find the value of x for which (x+2) ,2x and (2x+3) are three consecutive term of an AP
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Answered by
0
Answer:
Value of x is 5
Step-by-step explanation:
Given x+2,2x,2x+3 are in A.P.
⇒(2x)−(x+2)=(2x+3)−(2x)
2x−x−2=2x+3−2x
x−2=3
∴x=5
Value of x=5
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