johns mother age is two more than four times johns present age three years ago mother's age was one less than seven times johns age. find thier present age?
Answers
Answer:
The present age of John's father is 10 years more than twice the present age of John. After 10 years, age of John's father will be twice the John's age. Find their current ages...
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✒Given : -
The present age of John's father is 10 years more than twice the present age of John...
After 10 years, age of John's father will be twice the John's age...
✒To Find : -
Current ages = ?
✒Let ,
Present age of John's be = y
Then, Present age of his father will be = 2y + 10
✒After 10 years : -
John's age = y + 10
His father's age = 2y + 10 + 10
✒Now ,
{ \large{ \bold{ \underline{ \underline{ \purple{According\:to\:the\:Question:-}}}}}}
AccordingtotheQuestion:−
\dashrightarrow\sf{2y+10+10=2(y+10)+10}⇢2y+10+10=2(y+10)+10
✒On Substituting Values : -
\dashrightarrow\sf{2y+20=2y+20+10}⇢2y+20=2y+20+10
\sf⇢2y−2y=30−20⇢2y−2y=30−20
\leadsto\sf{{ \large{ \boxed{ \bold{ \bold{ \red{y=10}}}}}}}⇝
y=10
✒Therefore , Value of y is 10 ..
✒So ,
\dashrightarrow\sf{Present\:age\:of\:John(y)=10\:years}⇢PresentageofJohn(y)=10years
\dashrightarrow\sf{Present\:age\:of\:his\:Father=2y+10}⇢PresentageofhisFather=2y+10
\dashrightarrow\sf{2(10)+10}⇢2(10)+10
\dashrightarrow\sf{20+10}⇢20+10
\leadsto\sf\bold{30\:years}⇝30years
☃️Done !!
Answer:
Johns Mother age is 4x+2
Johns age is 7x-1
Please mark me as brainliest.
