Question

find the ValuE of X From Given Cicle Geometry

Answer 1

Hello mate !!!!!!

Here is your answer......

Join OB

OA = OB = OC ( radii of same circle)

Now in triangle AOB

AO = OB ( radii of circle)

So, < BAO = < ABO ( isosceles triangle property)

We get < ABO = 40°

Similarly in triangle BOC

OB = OC

SO,<BCO = < CBO

We get < CBO = 30°

< ABC = < ABO + < CBO

< ABC = 40 +30 = 70°

We know that ABCD is a cyclic quadrilateral.

So the sum of opposite angles is 180°

<ABC + < ADC = 180°

70°+ < ADC = 180°

< ADC = 180° - 70° = 110°

Therefore < ADC = 110°

HOPE THIS WILL HELP YOU.....