Question

Find the value of x , if 4^2x-1 = 32^2/5

Answer 1

Answer:

x= 1

Step-by-step explanation:

just simplify the things

4^(2x-1) = 32^(2/5)

write 4 as 2² and 32 as 2⁵

you will get

2^2(2x-1) = 2^5(2/5)

now base are same

so just compare the powers

4x-2 = 2

4x= 4

x= 4

hope you get it