Question

find the value of x if 5x degree and (6x+4) degree are supplymentary angles. Also, find the two angles?

Answer 1

$let \: both \: angles \: be \: {a}^{o} and \: {b}^{o}$

$5x + 6x + 4 = {180}^{o}$

$11x = 176$

$x = \frac{176}{11}$

$x = 16$

$angle \: a \: = \: {a}^{o} = 5x$

$= 5 \times 16$

$= {80}^{o}$

$angle \: b = {b}^{o} = 6x + 4$

$= 6 \times 16 + 4$

$= 96 + 4$

$= {100}^{o}$