Question

Find the value of x in the following
$\frac{9}{729} = (\frac{1}{9}) {}^{x}$
​

Answer 1

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81 −2 ÷729 1−x =9 2x

729 1−x

81 −2 =9 2x

(9 3 ) 1−x (92 ) −2

=92x 93(1−x) 9 −4

=9 2x

9 −4 =9 3−3x .9 2x

9 −4 =9 3−3x+2x

9 −4 =9 3−x

Comparing both side

Then,

−4=3−x

−4−3=−x−7=−x

x=7

Hence, it is required solution.

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