Question

given that two of the zeroes of the cubic polynomial ax3+bx2+cx+d are 0 the third zero is
(a) -b/a
(b) b/a
(c) c/a
(d) -d/a​

Answer 1

Any equation can be written as the product of its factors.

$(x - p)(x - q)(x - r) = 0$

$p = 0 \\ q = 0$

Thus,

$x = r$

Answer 2

Zero of the cubic polynomial will be

(D) $\frac {-d}{a}$