find the value of x in the trapezium abcd
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formula for trapezium
1/2×d1 +d2×h
there must be another value in the question
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Since ABCD is trapezium
AB||CD
So, Angle A + Angle D = 180° [alternate interior angles]
x-22+x+42 = 180
2x + 20 = 180
2x = 180 - 20
2x = 160
x=80
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