find the value of x in this equation
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it's so simple
{(-2/7)^2}^n ×(-7/2)^-1 = -8/343
{(-2/7)^2}^n × (-2/7) = -8/343
{(-2/7)^3}^n =(-2/7)^3
3n = 3
n = 1
{(-2/7)^2}^n ×(-7/2)^-1 = -8/343
{(-2/7)^2}^n × (-2/7) = -8/343
{(-2/7)^3}^n =(-2/7)^3
3n = 3
n = 1
Valenntine:
tnkeew
pls do that
may be 2x + 1 = 3 that is 2x = 3 - 1 that is 2x = 2 therefore x = 1. may be I am wrong
yea thats also correct thats an shortest way
pls check and tell me I got confused
on only considering the powers this one is correct
you are studying in which class
im studying finalyr btech
good. I am a maths teacher. God bless you
tq so much sir
Answered by
0
[{(-2/7)^2} ^x] (-7/2)^-1 = - 8 / 343
[{(-2/7)^2} ^x] (-2/7) = - 8 / 343
[{(-2/7)^2} ^x] (-2/7) = (-2/ 7)^3
Now just take exponents
2x + 1 = 3
2x = 3 - 1
2x = 2
x = 2 / 2
x = 1
[{(-2/7)^2} ^x] (-2/7) = - 8 / 343
[{(-2/7)^2} ^x] (-2/7) = (-2/ 7)^3
Now just take exponents
2x + 1 = 3
2x = 3 - 1
2x = 2
x = 2 / 2
x = 1
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