Question

find the value of x that is a solution to the equation:2√5x^2-13x+3√5=0​

Answer 1

Answer:

given equation is

2√5x² -13x + 3√5 = 0.

=> ,. 2√5x² - 10x - 3x + 3√5 = 0

=> 2√5x(x - √5) - 3( x - √5) = 0

=> ( x - √5)( 2√5x - 3) = 0

=> x - √5 = 0 ,or. 2√5x - 3 = 0

=> x = √5 or, 2√5x = 3

thus,

$\frac{3}{2 \sqrt{5} }$

or x = √5

hope it helps u..