find the value of x the distance between the point is( -4, 0) and (1, x) is root 50
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Step-by-step explanation:
d = √[(x2-x1)² + (y2-y1)²]
d = √50, x1 = -4, x2 = 1, y1 = 0 , y2 = x
√50 = √[(1 - (-4) + (x - 1)²]
√50 = ✓(5² + x² + 1 - 2x)
√50 = √(x² - 2x + 26)
50 = x² - 2x + 26 [ squaring both sides ]
=> x² - 2x - 24 = 0
=> x² - 6x + 4x - 24 = 0
=> x (x - 6) + 4 (x - 6) = 0
=> (x + 4) (x - 6) = 0
=> x + 4 = 0, => x = -4
=> x - 6 = 0, => x = 6
therefore x = - 4 and x = 6
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