Question

find the value of x where16:x::12:3​

Answer 1

hey the answer is. . . . . .

16 : x :: 12 : 3

product of means = product of extremes

x × 12 = 3 × 16

x = 4


hope it helps uu frnd

Answer 2

$\huge {\boxed{\boxed {\tt {Answer}}}}$

$\sf 16:x:12:3 \\ \\ \sf \implies \dfrac{16}{x}=\dfrac {12}{3} \\ \\ \sf \implies 12x=16×3 \\ \\ \sf \implies x=\dfrac {16×{\cancel{ 3}}}{\cancel{12}} \\ \\ \sf \implies x=\dfrac {16}{4}=4$

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