Question

find the value of y
$\ \textless \ br /\ \textgreater \ - 15 = \sqrt{ {y }^{2} } + \sqrt{6y}−15=y2​+6y​ \ \textless \ br /\ \textgreater$
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Answer 1

Step-by-step explanation:

$\\ {4}^{2} = 6y + \frac{30}{2} \\ 16 = 6y + 15 \\ 6y = 16 - 15 \\ 6y = 1 \\ y = \frac{1}{6}$

Answer 2

Answer:

$4 {}^{2} = y + \frac{30}{2}$

after solving it

y will be gives value of 1