Question

Find the value ok K for which one root of the quadratic equation (kx)2-14x+8=0 is six times the other

Answer 1

let first root ¢ and other 6¢

then, sum of roots = 6¢ + ¢ = 14/k

7¢ = 14/k

¢ = 2/k -----(1)

6¢^2 = 8/k

3¢^2 = 4/k ----(2)

put equation in equation (2)

3(2/k)^2 = 4/k

12/k^2 = 4/k

3/k = 1

k = 3