find the value ok k for which the quadratic equation x²-2kx+5k=0 has equal roots
Answers
Answered by
39
Heya user !!!
Here's the answer you are looking for
For a quadratic equation to have equal roots , b² - 4ac should be equal to zero.
Where b is the co-efficient of x
a is the co-efficient is x²
and c is the constant term.
Here, in x² - 2kx + 5k
a = 1
b = -2k
& c = 5k
we know b² - 4ac = 0
So,
(-2k)² - 4(1)(5k) = 0
4k² - 20k = 0
4 (k² - 5k) = 0
k² - 5k = 0/4 = 0
k ( k - 5) = 0
So k = 0 or k = 5
Therefore for k = 0 or 5 the quadratic equation will have equal roots.
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
For a quadratic equation to have equal roots , b² - 4ac should be equal to zero.
Where b is the co-efficient of x
a is the co-efficient is x²
and c is the constant term.
Here, in x² - 2kx + 5k
a = 1
b = -2k
& c = 5k
we know b² - 4ac = 0
So,
(-2k)² - 4(1)(5k) = 0
4k² - 20k = 0
4 (k² - 5k) = 0
k² - 5k = 0/4 = 0
k ( k - 5) = 0
So k = 0 or k = 5
Therefore for k = 0 or 5 the quadratic equation will have equal roots.
★★ HOPE THAT HELPS ☺️ ★★
sargamjitkaur:
i think there is a little mistake cause i put question of equation x²-2kx+5k but u answered of x²-2kx+5 can u pls see this answer again
done....
thxx
:-)
Answered by
5
The answer is K=5 as we know that sum of roots is -b/a and product of roots is c/a
Similar questions