Find the value/ s of k for which the quadratic equation 3x square+ kx +3 = 0 has real and equal roots
Answers
Answered by
2
Answer:
k = 6 and k = -6
Step-by-step explanation:
The quadratic ax²+bx+c has equal roots only if the discriminant b²-4ac is zero.
So...
3x² + kx + 3 = 0 has equal real roots
=> k² - (4)(3)(3) = 0
=> k² = (4)(3)(3) = 36
=> k = ±6.
Answered by
0
Answer:
Since the roots are real and equal, ∴ D = b
2 − 4ac = 0
⇒k
2 – 4×3×3 = 0 (∵ a = 3, b = k, c = 3)
⇒k
2 = 36
⇒k = 6 or −6
Similar questions