Question

Find the value(s) of k, if the quadratic equation 3x² − k √3 x + 4 = 0, has equal roots.

Answer 1

From equation, we get
a = 3
b = - k√3
c = 4

Discriminant = 0
[because equation has equal roots]

$b^2 - 4ac = 0 \\ \\ (- k\sqrt3)^2 - 4 * 3 * 4 = 0\\ \\ 3k^2 - 48 = 0\\ \\ 3k^2 = 48\\ \\ k^2 = \frac{48}{3} \\ \\ k = \sqrt16$

Ans. K = 4

Answer 2

Hi there!

Quadratic eqn.
3x² - k√3 x + 4 = 0

For equal roots,

Discriminant = 0

b² - 4ac = 0

(-k√3)² - 4(3)(4) = 0

3k² - 48 = 0

3k² = 48

k² = 48/3

k = ±√16

k = ± 4

[ Thank you! for asking the question. ]
Hope it helps!