Math, asked by yy693951, 7 months ago

Find the value when one ninth is divided by two third and one seventh is added to the product​

Answers

Answered by shriniwasmishra
1

Step-by-step explanation:

ANSWER

Let,

The number be x

Two-third of a number=

3

2

x

One-half of a number =

2

1

x

One-seventh of a number =

7

1

x

A.T.Q,

3

2

x+

2

1

x+

7

2

x+x=37

42

28x+21x+6x+42x

=37

42

97

x=37

⟹x=

97

37×42

⟹x=

97

1554

=16

97

2

Answered by GK1971
1

Answer:

13/42

Step-by-step explanation:

(1/9 ÷ 2/3) + 1/7

= (1/9 × 3/2) + 1/7 (Reciprocal)

= 1/6 + 1/7

= 7/42 + 6/42 ( L.C.M of the denominators )

= 13/42

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