Question

Find the values of 'c' for which the pair of equation cx-y=2 and 6x-2y=3 will have infinitely many sloution

Answer 1

Answer:

For no value of c the pair of equations will have infinitely many solutions.

Step-by-step explanation:

Given : The pair of equation $cx-y=2$ and $6x-2y=3$ will have infinitely many solution.

To find : The value of 'c'?

Solution :

Condition for infinitely many solutions is

$\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}$

Given lines are $cx-y=2$ and $6x-2y=3$

So, $a_1=c,b_1=-1,c_1=-2,a_2=6,b_2=-2,c_2=-3$

Substitute in the condition,

$\frac{c}{6}=\frac{-1}{-2}=\frac{-2}{-3}$

$\frac{c}{6}=\frac{1}{2}=\frac{2}{3}$

Take first two,

$\frac{c}{6}=\frac{1}{2}$

Solve,

$c=3$

Take first and last,

$\frac{c}{6}=\frac{2}{3}$

Solve,

$c=4$

Since, c has different values.

Hence, For no value of c the pair of equations will have infinitely many solutions.

Answer 2

Here is your solution buddy.....may this help u