Question

what is the oxidation number of chromium in cr2 O7 2-

Answer 1

Explanation:

Problem: What is the oxidation number (O.N.) of chromium (Cr) in the dichromate ion Cr2O72−?

Let the O.N. of Cr be x. The O.N. of oxygen is -2.

The sum of the oxidation states in an ion must add up to the charge on the ion. The dichromate ion has a charge of 2−, as indicated by its formula, Cr2O72−.

2⋅x + 7⋅(-2) = (-2)

2⋅x - 14 = -2

Add 14 to both the sides;

2⋅x -14 +14 = -2 +14

2⋅x = 12

Divide both sides by 2 ;

2x2 =122

x=6

The oxidation number of chromium in the dichromate ion is +6.
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Answer 2

Answer:

+6

Explanation:the answer is

On the image.

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