find the values of cosec ( - 11110° ).
Answers
Answered by
6
hello rihan^^
here is u r answer ^^
thank for asking this question ^^
_________________________________
180 ° = π©
= > ( -1110 ° ) = [ π / 180 × 1110 ]©
= > 【 37π / 6 】©
so ,
cosec (-1110°) = - cosec ( 1110°)
[ cosec ( - theta ) = - cosec theta.]
= > - cosec ( 37π / 6)
=> - cosec ( 6π + π / 6)
= > - cosec π /6 [ cosec(2nπ + theta) = cosec theta]
= > -2.
=====================================
I hope help u.
here is u r answer ^^
thank for asking this question ^^
_________________________________
180 ° = π©
= > ( -1110 ° ) = [ π / 180 × 1110 ]©
= > 【 37π / 6 】©
so ,
cosec (-1110°) = - cosec ( 1110°)
[ cosec ( - theta ) = - cosec theta.]
= > - cosec ( 37π / 6)
=> - cosec ( 6π + π / 6)
= > - cosec π /6 [ cosec(2nπ + theta) = cosec theta]
= > -2.
=====================================
I hope help u.
Similar questions
Biology,
7 months ago
English,
7 months ago
Computer Science,
7 months ago
CBSE BOARD XII,
1 year ago
Math,
1 year ago
Math,
1 year ago