Question

Find the values of k for which the equation has real roots 2x^2+kx+3=0(Ans k=-2√6 or 2√6)

Answer 1

Given 2x2 + kx + 3 = 0 has equal roots Hence b2 – 4ac = 0 That is (k)2 – 4(2)(3) = 0 k2 – 24 = 0 k2 = 24 ∴ k = ± 2√6