Math, asked by bhoomikak, 1 year ago

the sum of the digits of a two digit number is 13 the number obtained by interchanging its digit exceeds the given number by 9 find the original number

Answers

Answered by Shadowcryptic

let the tens digit be x and units digit be y
x+y=13. (1)
original number =10x+y
by interchanging the digits= 10y+x
(10y+x)-(10x+y)=9
10y+x-10x+y=9
10y-y-10x-x=9
9y-9x=9
9(y-x)=9
y-x=1
(13-x)-x=1 (using (1))
13-2x=1
2x=12
x=6
y=13-6
y=7
hence the required number= 67

bhoomikak: i tried to send one but

Shadowcryptic: i also tried.

bhoomikak: i didnt see what yiu sent on insta

bhoomikak: i sent the request even to tanisha but she has not seen it yet

Shadowcryptic: oh. i sent the screenshot of this account cos i knew u won't recognize

bhoomikak: bye i must practice otherwise my mom will kill me

Shadowcryptic: Tanisha also there?

Shadowcryptic: ok all the best. bye

bhoomikak: shes not there bye

Shadowcryptic: bye

Previous Question

Next Question