find the values of P and q for which the
following system of equation has infinitely
may solution
2x-3y=7
(P+q)x-(p+q-3) y=40+q
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Step-by-step explanation:
2x + 3y = 7
(p+q)x + (2p-q)y = 21
For equations to have infinite solutions:
- a1/a2=b1/b2=c1/c2
- 2/p+q=3/2p-q=7/21
- 2/p+q=3/2p-q=1/3
- p+q=6......(I)
- and
- 3/2p-q=1/3
- =2p-q=9.....(ii)
- 2p+2q=12
- 4p-2q=18
- ---------
- 6p=30
- p=5
- substitute p in (I)
- p+q=6
- 5+q=6
- q=1
- therefore ,p=5 and q=1
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