Question

find the values of x and y​

Answer 1

Required Answer ✌️

In Quadrilateral ABCD :-

∠A + ∠B + ∠C + ∠D = 360

(∴ Sum of All Angles of a Closed Fig. is Equals to 360°)

→ (2y+4 + y+10) + (5x+5 + 4x-4) = 360°

→ (3y + 14) + (9x + 1) = 360°

→ 9x + 3y + 15 = 360°

→ 9x + 3y = (360 - 15) = 345 °

→ 9x + 3y - 345 = 0

→ 3x + y - 115 = 0

Now Using Quadratic Formula :-

x = $\frac{ -b \pm \sqrt{b^2 - 4ac}}{2a}$

• a, b, c = constants, where a ≠ 0
• x = The Unknown

Thanking You ✌️

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