Math, asked by mikey30, 11 months ago

find the values of x and y satisfying the given equations x2+y2 =36 and x/2+y=1​

Answers

Answered by Anonymous
3

Answer:

2x+2y= 36.

X/2+y= 1

From eq1 and eq2*2

2x+2y = 36

X +2y = 2

X. = 34

Putting the value of x in eq1

2*34 + 2y = 36

68 +2y =36

2[34 +y] =36

34 + y = 18

Y = 18 - 34

Y = - 17

Answered by pavit15
0

Answer:

Answer:

2x+2y= 36.

X/2+y= 1

From eq1 and eq2*2

2x+2y = 36

X +2y = 2

X. = 34

Putting the value of x in eq1

2*34 + 2y = 36

68 +2y =36

2[34 +y] =36

34 + y = 18

Y = 18 - 34

Y = - 17

Step-by-step explanation:

Similar questions