Question

Find the vector equation of the line passing through the point (2.-3.-4) and perpendicular to the lines x/2 = y-2/1= z-1/-1 and x+3/3 = y+2/-2 = z-4/4​

Answer 1

Step-by-step explanation:

Let the equation of line be

a

x−1

=

b

y−2

=

c

z+4

Now the line is parallel to the two given points so we get

(3

i

−16

j

+7

k

)×(3

i

+8

j

−5

k

)

=24

i

+36

j

+72

k

=2

i

+3

j

+6

k

[taking12commom]

Hence,

The required equation is

2

x−1

=

3

y−2

=

6

z+4

Answer 2

Le baa bhosdi wale kar diya follow tere ko aab mere ko bhi follow kar samjha be kamina