find the volue of 1-sin ^ 2a if a=30
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L.H.S. = sin 2A
Putting A = 30˚ in L.H.S. and R.H.S., we get
L.H.S. = sin 2 × 30˚= sin 60˚ = √3/2
R.H.S. = 2 × tan 30˚/1 + tan2 30˚ = (2 × 1/√3)/(1 + (1/√3)2
= (2/√3)/(1 + 1/3) = (2/√3)/(4/3)
= 2 × 3/√3 × 4 = √3/2
Hence,
L.H.S. = R.H.S.
Hence proved.
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