Question

Find the volume,C.S.A and the T.S.A of a cone whose height and slant height are 6 cm and 10 cm respectively.

Answer 1

h = 6cm
l = 10 cm
r =
$\sqrt{10 { }^{2} - 6 {}^{2} } = \sqrt{64 } = 8$
csa= πrl =
$22 \times 8 \times 10 \div 7 = 251.43cm { }^{2}$
tsa=πr(l+r)
$22 \times 8(10 + 8) \div 7 = 22 \times 8 \times 18 \div 7 = 452.57cm {}^{2}$
volume=
$\frac{1}{3} \pi \: r {}^{2}h = \frac{1}{3} \times \frac{22}{7} \times 8 \times 8 \times 6 = 402.28cm^{3}$