Find the volume of Co2 obtained at STP by heating 50 grams of caco3?( atomic mass of CA is 40 C is 12 16)
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Answer:
The answer is 11.2 L
Explanation:
on heating CaCO₃
1 mole of CaCO₃ gives 1 mole of CO₂
at STP 1 mole = 22.4 L
given :
50 grams of CaCO₃ is heated .
which is equal to 0.5 mole.
so , 0.5 mole of CaCO₃ gives 0.5 mole of CO₂.
0.5 moles = 11.2 L ( at STP )
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Answer:
Explanation: I realy don't know
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