Question

Find the wavelength of the emitted radiation when electrons and holes in this semiconductor recombine directly. Here, the band gap for an alloy of semiconductor is 1.98 eV

Answer 1

Given:

Band gap energy $E_{g} = 1.98$ eV

To Find:

Find the wavelength of the emitted radiation,

According to the planck's law,

    $E_{g} = \frac{hc}{\lambda}$

Where $h = 6.626 \times 10^{-34}$, $c = 3 \times 10^{8} \frac{m}{s}$

For finding wavelength,

   $\lambda = \frac{hc}{E_{g} }$

   $\lambda = \frac{6.626 \times 10^{-34} \times 3 \times 10^{8} }{1.98 \times 1.6 \times 10^{-19} }$

   $\lambda = 6.274 \times 10^{-7}$ m

Therefore, the wavelength of emitted radiation is $6.274 \times 10^{-7}$ m