Question

Find the zero of the polynomial 2x square + 7 x minus 4

Answer 1

$Heya$‼

$Given\:equation:2x^2+7x-4$

$2x^2+7x-4=0$

$2x^2+8x-x-4=0$

$2x(x+4)-(x+4)=0$

$(2x-1)(x+4)=0$

$(2x-1)=0\:or\:(x-4)=0$

$x=\frac{1}{2}\:or\:x=-4$

Answer 2

Given,

• The polynomial $2x^2+7x-4$ is given.

To find,

• We have to find the zero of the polynomial.

Solution,

We can simply find the zero of the given polynomial by equating the polynomial to 0.

                $2x^2+7x-4$ = 0

Now, factorizing the above quadratic polynomial, we get

                 $2x^2 +(8-1)x-4$

                $2x^2+8x-x-4$

Now, taking 2x common from the first two terms and -1 common from the last two terms, we get

                $2x(x+4)-1(x+4)$

Now, taking (x+4) common, we get

                   $(x+4)(2x-1)$ = 0

                    (x+4) = 0  , (2x-1) = 0

                         x = -4,       x = 1/2

Hence, the zeroes of the polynomial $2x^2+7x-4$ are -4 and 1/2.