find the zero of the polynomial in p(x)=3x+1
Answers
Answered by
122
p(x) = 3x+1
put p(x) =0
3x+1=0
3x = -1
x = -1/3
CHECK
3(-1/3)+1
-1+1
=0
hence proved
put p(x) =0
3x+1=0
3x = -1
x = -1/3
CHECK
3(-1/3)+1
-1+1
=0
hence proved
Anonymous:
solve
this
if f(x) = x^2 -4x+6 find f(1) - f(-1)
please
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thanks
ya sure...wait a min
f(x) =x^2 - 4x + 6 ..... when f(1) = 1^2 -4(1)+6..........=1-4+6......=3
when f(-1)= -1^2 -4(-1)+6..........=1+4+6=11
hope it helps u
Answered by
4
Answer:
-1/3
Step-by-step explanation:
p(x)= 3x+1
p(x)=0
3x+1=-1/3
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